Given an array nums with n objects colored red, white, or blue, sort them in-place so that objects of the same color are adjacent, with the colors in the order red, white, and blue.
We will use the integers 0, 1, and 2 to represent the color red, white, and blue, respectively.
You must solve this problem without using the library’s sort function.
Example 1:
Input: nums = [2,0,2,1,1,0]
Output: [0,0,1,1,2,2]
Example 2:
Input: nums = [2,0,1]
Output: [0,1,2]
Constraints:
n == nums.length1 <= n <= 300nums[i]is either0,1, or2.
Follow up: Could you come up with a one-pass algorithm using only constant extra space?
Approach - Dutch flag (3 pointers)
- We have 3 options if it is 0 then swap with front if 1 then let it be there if 2 then swap with last
- It is basically a question asking us to sort the array but simple sorts will at max give us
nlognand not n which we get here - Time:
O(n)Space:O(1)
class Solution {
public void sortColors(int[] nums) {
int low = 0, mid = 0, high = nums.length - 1;
while (mid <= high) {
if (nums[mid] == 0)
swap(nums, low++, mid++);
else if (nums[mid] == 1)
mid++;
else
swap(nums, mid, high--);
}
}
void swap(int[] nums, int a, int b) {
int t = nums[b];
nums[b] = nums[a];
nums[a] = t;
}
}