Given the root of a binary search tree, and an integer k, return the kth smallest value (1-indexed) of all the values of the nodes in the tree.
Example 1:

Input: root = [3,1,4,null,2], k = 1
Output: 1
Example 2:

Input: root = [5,3,6,2,4,null,null,1], k = 3
Output: 3
Constraints:
- The number of nodes in the tree is
n. 1 <= k <= n <= 1040 <= Node.val <= 104
Follow up: If the BST is modified often (i.e., we can do insert and delete operations) and you need to find the kth smallest frequently, how would you optimize?
Approach - Iterative
- Keep pushing left elements then start popping and then push starting from right
Time: O(n) Space: O(n)
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public int kthSmallest(TreeNode root, int k) {
TreeNode c = root;
Stack<TreeNode> s = new Stack<>();
// In-order traversal using stack
while (!s.isEmpty() || c != null) {
// Go to the leftmost node
while (c != null) {
s.push(c);
c = c.left;
}
// Pop the node from the stack and process it
c = s.pop();
k--;
if (k == 0) return c.val;
// Move to the right subtree
c = c.right;
}
return -1;
}
}