Given an integer array nums, find the subarray with the largest sum, and return its sum.
Example 1:
Input: nums = [-2,1,-3,4,-1,2,1,-5,4]
Output: 6
Explanation: The subarray [4,-1,2,1] has the largest sum 6.
Example 2:
Input: nums = [1]
Output: 1
Explanation: The subarray [1] has the largest sum 1.
Example 3:
Input: nums = [5,4,-1,7,8]
Output: 23
Explanation: The subarray [5,4,-1,7,8] has the largest sum 23.
Constraints:
1 <= nums.length <= 105-104 <= nums[i] <= 104
Follow up: If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.
Approach
Kadane'salgorithm -> if sum negative then set it to zero- For max sum initial to be set as first element
Time: O(n) Space: O(1)
class Solution {
public int maxSubArray(int[] nums) {
int s = 0, m = nums[0];
for (int n : nums) {
if (s < 0)
s = 0;
s += n;
m = Math.max(m, s);
}
return m;
}
}